What is expand 2z(e^{xyz}xyz+e^{xyz}) ?

The solution to expand 2z(e^{xyz}xyz+e^{xyz}) is 2e^{zxy}z^2xy+2e^{zxy}z

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expand 2z(e^{xyz}xyz+e^{xyz})

expand

2 z (e^{x yz} x yz + e^{x yz})

2 e^{z x y} z^{2} x y + 2 e^{z x y} z

Solution steps

2 z (e^{x yz} x yz + e^{x yz})

= 2 z (e^{z x y} z x y + e^{z x y})

Apply the distributive law:

a (b + c) = ab + a c

a = 2 z, b = e^{x yz} x yz, c = e^{x yz}

= 2 z e^{x yz} x yz + 2 z e^{x yz}

= 2 e^{z x y} zz x y + 2 e^{z x y} z

2 e^{z x y} zz x y = 2 e^{z x y} z^{2} x y

= 2 e^{z x y} z^{2} x y + 2 e^{z x y} z

(x + 2) (\frac{22}{x} + 2)

- \frac{10}{( x - 2 ) ^{3}}

a 3 (a + 33)

(56 sin (7 t) - 33 cos (7 t))^{2}

5 x - 6 \cdot x + 8

What is expand 2z(e^{xyz}xyz+e^{xyz}) ?
The solution to expand 2z(e^{xyz}xyz+e^{xyz}) is 2e^{zxy}z^2xy+2e^{zxy}z