What is expand x^{2/3}(2x-5) ?

The solution to expand x^{2/3}(2x-5) is 2x^{5/3}-x^{2/3}*5

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expand x^{2/3}(2x-5)

expand

x^{\frac{2}{3}} (2 x - 5)

2 x^{\frac{5}{3}} - x^{\frac{2}{3}} \cdot 5

Solution steps

x^{\frac{2}{3}} (2 x - 5)

Apply the distributive law:

a (b - c) = ab - a c

x^{\frac{2}{3}} (2 x - 5) = x^{\frac{2}{3}} \cdot 2 x - x^{\frac{2}{3}} \cdot 5

= x^{\frac{2}{3}} \cdot 2 x - x^{\frac{2}{3}} \cdot 5

Simplify

x^{\frac{2}{3}} \cdot 2 x : 2 x^{\frac{5}{3}}

= 2 x^{\frac{5}{3}} - x^{\frac{2}{3}} \cdot 5

\frac{x ^{2} + 2 x - 4}{( x + 1 ) ^{2}}

t + H (t - π) (2 (t - π) + H (t - π))

(y^{3} x^{2} + 2 y) d x + x^{2} y^{3} (4 y d x + 5 x d y)

3 in (e^{x} + 1)

(3 - e^{t})^{2}

What is expand x^{2/3}(2x-5) ?
The solution to expand x^{2/3}(2x-5) is 2x^{5/3}-x^{2/3}*5