What is expand (14x-28)e^{x^2-4x} ?

The solution to expand (14x-28)e^{x^2-4x} is 14e^{x^2-4x}x-28e^{x^2-4x}

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expand (14x-28)e^{x^2-4x}

expand

(14 x - 28) e^{x^{2} - 4 x}

14 e^{x^{2} - 4 x} x - 28 e^{x^{2} - 4 x}

Solution steps

(14 x - 28) e^{x^{2} - 4 x}

= e^{x^{2} - 4 x} (14 x - 28)

Apply the distributive law:

a (b - c) = ab - a c

a = e^{x^{2} - 4 x}, b = 14 x, c = 28

= e^{x^{2} - 4 x} \cdot 14 x - e^{x^{2} - 4 x} \cdot 28

= 14 e^{x^{2} - 4 x} x - 28 e^{x^{2} - 4 x}

\frac{d}{d t} ((z (t, x, y)) (6 x^{2} + 3 x y (t)^{2}))

(x - (- 1 + i)) (x - (- 1 - i))

((X Y) + Z) \Rightarrow W

x^{4} (e^{x} x - e^{x})

\frac{2 ( 7 - 19 )}{3}

What is expand (14x-28)e^{x^2-4x} ?
The solution to expand (14x-28)e^{x^2-4x} is 14e^{x^2-4x}x-28e^{x^2-4x}