What is expand log_{10}(3)(x^2-1) ?

The solution to expand log_{10}(3)(x^2-1) is log_{10}(3)x^2-log_{10}(3)

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expand log_{10}(3)(x^2-1)

expand

lo g_{10} (3) (x^{2} - 1)

lo g_{10} (3) x^{2} - lo g_{10} (3)

Solution steps

lo g_{10} (3) (x^{2} - 1)

Apply the distributive law:

a (b - c) = ab - a c

lo g_{10} (3) (x^{2} - 1) = lo g_{10} (3) x^{2} - lo g_{10} (3) \cdot 1

= lo g_{10} (3) x^{2} - lo g_{10} (3) \cdot 1

Apply rule:

a \cdot 1 = a

- lo g_{10} (3) \cdot 1 = - lo g_{10} (3)

= lo g_{10} (3) x^{2} - lo g_{10} (3)

\frac{e ^{- 7 x} - 2 x + 6}{( x - 3 ) ( x - 1 )}

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What is expand log_{10}(3)(x^2-1) ?
The solution to expand log_{10}(3)(x^2-1) is log_{10}(3)x^2-log_{10}(3)