What is (4-(x^2)/3)(4+(x^2)/3) ?

The solution to (4-(x^2)/3)(4+(x^2)/3) is ((12-x^2)(12+x^2))/9

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simplify (4-(x^2)/3)(4+(x^2)/3)

simplify

(4 - \frac{x ^{2}}{3}) (4 + \frac{x ^{2}}{3})

\frac{( 12 - x ^{2} ) ( 12 + x ^{2} )}{9}

Solution steps

(4 - \frac{x ^{2}}{3}) (4 + \frac{x ^{2}}{3})

Join

4 - \frac{x ^{2}}{3} : \frac{12 - x ^{2}}{3}

= \frac{12 - x ^{2}}{3} (4 + \frac{x ^{2}}{3})

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 12 - x ^{2} ) ( 4 + \frac{x ^{2}}{3} )}{3}

Simplify

(12 - x^{2}) (4 + \frac{x ^{2}}{3}) : \frac{( 12 - x ^{2} ) ( 12 + x ^{2} )}{3}

= \frac{\frac{( 12 - x ^{2} ) ( 12 + x ^{2} )}{3}}{3}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{( 12 - x ^{2} ) ( 12 + x ^{2} )}{3 \cdot 3}

Multiply the numbers:

3 \cdot 3 = 9

= \frac{( 12 - x ^{2} ) ( 12 + x ^{2} )}{9}

\frac{( x ^{3} + 6 ) ^{2}}{225}

\frac{8 x ^{2} - 6 x}{( 8 x - 3 ) ^{2}}

4 (5 x - 7 = 10 x + 2)

\frac{1}{s ( s + 1 ) ( s + 5 ) ( s + 10 )}

(X^{2} \circ X - 2) (4)

What is (4-(x^2)/3)(4+(x^2)/3) ?
The solution to (4-(x^2)/3)(4+(x^2)/3) is ((12-x^2)(12+x^2))/9