What is expand ((5x+4)/(x^2-4))((4x+2)/(x^2-4)) ?

The solution to expand ((5x+4)/(x^2-4))((4x+2)/(x^2-4)) is (20x^2+26x+8)/(x^4-8x^2+16)

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expand ((5x+4)/(x^2-4))((4x+2)/(x^2-4))

expand

(\frac{5 x + 4}{x ^{2} - 4}) (\frac{4 x + 2}{x ^{2} - 4})

\frac{20 x ^{2} + 26 x + 8}{x ^{4} - 8 x ^{2} + 16}

Solution steps

(\frac{5 x + 4}{x ^{2} - 4}) (\frac{4 x + 2}{x ^{2} - 4})

Remove parentheses:

(a) = a

= \frac{5 x + 4}{x ^{2} - 4} \cdot \frac{4 x + 2}{x ^{2} - 4}

Multiply fractions:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{( 5 x + 4 ) ( 4 x + 2 )}{( x ^{2} - 4 ) ( x ^{2} - 4 )}

(x^{2} - 4) (x^{2} - 4) = (x^{2} - 4)^{2}

= \frac{( 5 x + 4 ) ( 4 x + 2 )}{( x ^{2} - 4 ) ^{2}}

(x^{2} - 4)^{2} = x^{4} - 8 x^{2} + 16

= \frac{( 5 x + 4 ) ( 4 x + 2 )}{x ^{4} - 8 x ^{2} + 16}

Expand

(5 x + 4) (4 x + 2) : 20 x^{2} + 26 x + 8

= \frac{20 x ^{2} + 26 x + 8}{x ^{4} - 8 x ^{2} + 16}

(R + \frac{t}{2})^{4}

\frac{a + 3}{( a + 8 ) ( a - 3 )}

(2 + 3)^{10} (2 - 3)^{10}

(x^{3} + 3 x y^{2}) d x + (y^{3} + 3 x^{2} y) d y

What is expand ((5x+4)/(x^2-4))((4x+2)/(x^2-4)) ?
The solution to expand ((5x+4)/(x^2-4))((4x+2)/(x^2-4)) is (20x^2+26x+8)/(x^4-8x^2+16)