What is expand (s^2-2s-4)/(6(s^3-3s^2-3s-1)) ?

The solution to expand (s^2-2s-4)/(6(s^3-3s^2-3s-1)) is (s^2-2s-4)/(6s^3-18s^2-18s-6)

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expand (s^2-2s-4)/(6(s^3-3s^2-3s-1))

expand

\frac{s ^{2} - 2 s - 4}{6 ( s ^{3} - 3 s ^{2} - 3 s - 1 )}

\frac{s ^{2} - 2 s - 4}{6 s ^{3} - 18 s ^{2} - 18 s - 6}

Solution steps

\frac{s ^{2} - 2 s - 4}{6 ( s ^{3} - 3 s ^{2} - 3 s - 1 )}

Expand

6 (s^{3} - 3 s^{2} - 3 s - 1) : 6 s^{3} - 18 s^{2} - 18 s - 6

= \frac{s ^{2} - 2 s - 4}{6 s ^{3} - 18 s ^{2} - 18 s - 6}

x^{2} (1 - y^{2}) \frac{d y}{d x} + y^{2} (1 + x)

2 (5 - 4)

\frac{x ^{2} - 4}{x ^{2} + 6 x + 9} \cdot \frac{x - 3}{x ^{3} - 9}

i (i z^{3} - 2 z)^{6} (3 z^{4} - z^{2} + 2 z + i z^{4})

(x - 2) \cdot (2 x - 5)

What is expand (s^2-2s-4)/(6(s^3-3s^2-3s-1)) ?
The solution to expand (s^2-2s-4)/(6(s^3-3s^2-3s-1)) is (s^2-2s-4)/(6s^3-18s^2-18s-6)