What is expand q(65=(300)/((q^2+9)^{1/2)}+74.25) ?

The solution to expand q(65=(300)/((q^2+9)^{1/2)}+74.25) is 65q=(300)/((q^2+9)^{1/2)}+74.25q

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expand q(65=(300)/((q^2+9)^{1/2)}+74.25)

expand

q (65 = \frac{300}{( q ^{2} + 9 ) ^{\frac{1}{2}}} + 74.25)

65 q = \frac{300}{( q ^{2} + 9 ) ^{\frac{1}{2}}} + 74.25 q

Solution steps

q (65 = \frac{300}{( q ^{2} + 9 ) ^{\frac{1}{2}}} + 74.25)

Apply the distributive law:

a (b + c) = ab + a c

a = q, b = 65 = \frac{300}{( q ^{2} + 9 ) ^{\frac{1}{2}}}, c = 74.25

q \cdot 65 = \frac{300}{( q ^{2} + 9 ) ^{\frac{1}{2}}} + q \cdot 74.25

65 q = \frac{300}{( q ^{2} + 9 ) ^{\frac{1}{2}}} + 74.25 q

(\frac{8 π}{3} - 43) c m^{2}

\frac{1 + a ^{2} + 4 a}{a ( a + 1 )}

- 3 (2 r - \frac{3}{11})

What is expand q(65=(300)/((q^2+9)^{1/2)}+74.25) ?
The solution to expand q(65=(300)/((q^2+9)^{1/2)}+74.25) is 65q=(300)/((q^2+9)^{1/2)}+74.25q