What is (x-3)(x+1)(x-1/2)(x-5) ?

The solution to (x-3)(x+1)(x-1/2)(x-5) is ((x-3)(x+1)(2x-1)(x-5))/2

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simplify (x-3)(x+1)(x-1/2)(x-5)

simplify

(x - 3) (x + 1) (x - \frac{1}{2}) (x - 5)

\frac{( x - 3 ) ( x + 1 ) ( 2 x - 1 ) ( x - 5 )}{2}

Solution steps

(x - 3) (x + 1) (x - \frac{1}{2}) (x - 5)

Simplify

x - \frac{1}{2} : \frac{2 x - 1}{2}

= (x - 3) (x + 1) \frac{2 x - 1}{2} (x - 5)

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( x - 3 ) ( x + 1 ) ( 2 x - 1 ) ( x - 5 )}{2}

(6 x^{6} - x^{2} y) + (- x^{3} + x^{2} y^{2}) y^{'} (x)

e^{5 x} (5 x e^{5 x} + e^{5 x})

(sin (x) + c)^{2}

(1 + cos (4 w))^{2} + (sin (4 w))^{2}

(- 10, - 4, 2) x (5, 2, 0)

What is (x-3)(x+1)(x-1/2)(x-5) ?
The solution to (x-3)(x+1)(x-1/2)(x-5) is ((x-3)(x+1)(2x-1)(x-5))/2