What is expand (2-2x)/(2y-3y^2+1)(1,-1) ?

The solution to expand (2-2x)/(2y-3y^2+1)(1,-1) is 1*(2-2x)/(2y-3y^2+1),-1*(2-2x)/(2y-3y^2+1)

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expand (2-2x)/(2y-3y^2+1)(1,-1)

expand

\frac{2 - 2 x}{2 y - 3 y ^{2} + 1} (1, - 1)

1 \cdot \frac{2 - 2 x}{2 y - 3 y ^{2} + 1}, - 1 \cdot \frac{2 - 2 x}{2 y - 3 y ^{2} + 1}

Solution steps

\frac{2 - 2 x}{2 y - 3 y ^{2} + 1} (1, - 1)

= (1, - 1) \frac{2 - 2 x}{2 y - 3 y ^{2} + 1}

Apply the distributive law:

a (b - c) = ab - a c

a = \frac{2 - 2 x}{2 y - 3 y ^{2} + 1}, b = 1,, c = 1

= \frac{2 - 2 x}{2 y - 3 y ^{2} + 1} \cdot 1, - \frac{2 - 2 x}{2 y - 3 y ^{2} + 1} \cdot 1

= 1 \cdot \frac{2 - 2 x}{2 y - 3 y ^{2} + 1}, - 1 \cdot \frac{2 - 2 x}{2 y - 3 y ^{2} + 1}

1 + k \cdot (- \frac{2.414}{s ^{2} + 0.666 s + 1.207} - 0.4)

\frac{8 x ^{2} - 56 x - 21}{( 2 x - 7 ) ^{2}}

\frac{6}{s ( s ^{2} + 9 )}

(3 + 5) (- 3 - 21)

π (n - 2)

What is expand (2-2x)/(2y-3y^2+1)(1,-1) ?
The solution to expand (2-2x)/(2y-3y^2+1)(1,-1) is 1*(2-2x)/(2y-3y^2+1),-1*(2-2x)/(2y-3y^2+1)