What is (x-1/2)(x+4)(x+3) ?

The solution to (x-1/2)(x+4)(x+3) is ((2x-1)(x+4)(x+3))/2

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simplify (x-1/2)(x+4)(x+3)

simplify

(x - \frac{1}{2}) (x + 4) (x + 3)

\frac{( 2 x - 1 ) ( x + 4 ) ( x + 3 )}{2}

Solution steps

(x - \frac{1}{2}) (x + 4) (x + 3)

Simplify

x - \frac{1}{2} : \frac{2 x - 1}{2}

= \frac{2 x - 1}{2} (x + 4) (x + 3)

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 2 x - 1 ) ( x + 4 ) ( x + 3 )}{2}

(2 sin (θ) - 1) (sin (θ) + 1)

\frac{( 1 + ab ) ^{2}}{( 1 - a ^{2} ) ( 1 - b ^{2} )}

cos (2 \cdot t) U (t - π)

(tan (θ) + cot (θ)) sin (θ)

0 sin (0)

What is (x-1/2)(x+4)(x+3) ?
The solution to (x-1/2)(x+4)(x+3) is ((2x-1)(x+4)(x+3))/2