What is expand (pi(9-x^2)(x+3))/3 ?

The solution to expand (pi(9-x^2)(x+3))/3 is -(pix^3)/3-pix^2+3pix+9pi

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expand (pi(9-x^2)(x+3))/3

expand

\frac{π ( 9 - x ^{2} ) ( x + 3 )}{3}

- \frac{π x ^{3}}{3} - π x^{2} + 3 π x + 9 π

Solution steps

\frac{π ( 9 - x ^{2} ) ( x + 3 )}{3}

Expand

π (9 - x^{2}) (x + 3) : 9 π x + 27 π - π x^{3} - 3 π x^{2}

= \frac{9 π x + 27 π - π x ^{3} - 3 π x ^{2}}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{9 π x + 27 π - π x ^{3} - 3 π x ^{2}}{3} = \frac{9 π x}{3} + \frac{27 π}{3} - \frac{π x ^{3}}{3} - \frac{3 π x ^{2}}{3}

= \frac{9 π x}{3} + \frac{27 π}{3} - \frac{π x ^{3}}{3} - \frac{3 π x ^{2}}{3}

Divide the numbers:

\frac{9}{3} = 3

= 3 π x + \frac{27 π}{3} - \frac{π x ^{3}}{3} - \frac{3 π x ^{2}}{3}

Divide the numbers:

\frac{27}{3} = 9

= 3 π x + 9 π - \frac{π x ^{3}}{3} - \frac{3 π x ^{2}}{3}

Divide the numbers:

\frac{3}{3} = 1

= 3 π x + 9 π - \frac{π x ^{3}}{3} - π x^{2}

Rewrite in standard form

= - \frac{π x ^{3}}{3} - π x^{2} + 3 π x + 9 π

\frac{3 ( 4 + 5 )}{22}

(4 + 3 sin (x))^{2}

x^{2} e^{2 x} (3 + 2 x)

\frac{2 ( t ^{2} + 1 - 2 t )}{( t ^{2} + 1 ) ^{2}}

\frac{5 ( 5 + 65 )}{4}

What is expand (pi(9-x^2)(x+3))/3 ?
The solution to expand (pi(9-x^2)(x+3))/3 is -(pix^3)/3-pix^2+3pix+9pi