What is expand (bcos(z)-asin(z)y)*2rsin(z) ?

The solution to expand (bcos(z)-asin(z)y)*2rsin(z) is brsin(2z)-2ayrsin^2(z)

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expand (bcos(z)-asin(z)y)*2rsin(z)

expand

(b cos (z) - a sin (z) y) \cdot 2 r sin (z)

b r sin (2 z) - 2 a yr sin^{2} (z)

Solution steps

(b cos (z) - a sin (z) y) \cdot 2 r sin (z)

= 2 r sin (z) (b cos (z) - a sin (z) y)

Apply the distributive law:

a (b - c) = ab - a c

2 r sin (z) (b cos (z) - a sin (z) y) = 2 r sin (z) b cos (z) - 2 r sin (z) a sin (z) y

= 2 r sin (z) b cos (z) - 2 r sin (z) a sin (z) y

Simplify

2 r sin (z) b cos (z) - 2 r sin (z) a sin (z) y : b r sin (2 z) - 2 a yr sin^{2} (z)

= b r sin (2 z) - 2 a yr sin^{2} (z)

\frac{3}{e ( \frac{a}{x} - 2 ) - 1}

\frac{3 s - 14}{( s - 2 ) ( s - 5 )}

(2 m + 4) - \frac{2 ( 5 m + 1 )}{5}

(sin^{4} (x) + cos^{4} (x) - 1) (sec^{2} (x) + csc^{2} (x))

(= e^{- x} x^{2} + 2 e^{- x} x + 2 e^{- x}) x

What is expand (bcos(z)-asin(z)y)*2rsin(z) ?
The solution to expand (bcos(z)-asin(z)y)*2rsin(z) is brsin(2z)-2ayrsin^2(z)