What is (1/3-x)(1/2-x) ?

The solution to (1/3-x)(1/2-x) is ((-3x+1)(-2x+1))/6

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simplify (1/3-x)(1/2-x)

simplify

(\frac{1}{3} - x) (\frac{1}{2} - x)

\frac{( - 3 x + 1 ) ( - 2 x + 1 )}{6}

Solution steps

(\frac{1}{3} - x) (\frac{1}{2} - x)

Simplify

\frac{1}{3} - x : \frac{- 3 x + 1}{3}

= \frac{- 3 x + 1}{3} (\frac{1}{2} - x)

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( - 3 x + 1 ) ( \frac{1}{2} - x )}{3}

Simplify

(- 3 x + 1) (\frac{1}{2} - x) : \frac{( - 3 x + 1 ) ( - x \cdot 2 + 1 )}{2}

= \frac{\frac{( - 3 x + 1 ) ( - x \cdot 2 + 1 )}{2}}{3}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{( - 3 x + 1 ) ( - x \cdot 2 + 1 )}{2 \cdot 3}

Multiply the numbers:

2 \cdot 3 = 6

= \frac{( - 3 x + 1 ) ( - x \cdot 2 + 1 )}{6}

= \frac{( - 3 x + 1 ) ( - 2 x + 1 )}{6}

- x^{2} - 1

\frac{d y}{d x} + y (x e^{x^{2}} + 1)

49 (2 + \frac{π}{4})

\frac{27 x ^{\frac{4}{3}} + 3 ( x ^{3} + 5 )}{x ^{\frac{2}{3}}}

(a - 3 e)^{2}