What is expand e/(3(n+1)(3n+2)(3n+1)) ?

The solution to expand e/(3(n+1)(3n+2)(3n+1)) is e/(27n^3+54n^2+33n+6)

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expand e/(3(n+1)(3n+2)(3n+1))

expand

\frac{e}{3 ( n + 1 ) ( 3 n + 2 ) ( 3 n + 1 )}

\frac{e}{27 n ^{3} + 54 n ^{2} + 33 n + 6}

Solution steps

\frac{e}{3 ( n + 1 ) ( 3 n + 2 ) ( 3 n + 1 )}

Expand

3 (n + 1) (3 n + 2) (3 n + 1) : 27 n^{3} + 54 n^{2} + 33 n + 6

= \frac{e}{27 n ^{3} + 54 n ^{2} + 33 n + 6}

(x - 2 + i)^{2}

(1250 - x) + (- \frac{5100}{( 0.02 x + 1 ) ^{2}})

\frac{- x ^{2} + 12 x - 35}{( x ^{2} - 6 x + 1 ) ^{2}}

(2 x - 4) (2 x^{2} - 8 x + 35)^{4} d x

\frac{1250 x + 750}{( 25 x ^{2} - 30 x + 9 ) ^{2}}

What is expand e/(3(n+1)(3n+2)(3n+1)) ?
The solution to expand e/(3(n+1)(3n+2)(3n+1)) is e/(27n^3+54n^2+33n+6)