What is expand (x^2-10x-41)/((x+1)(x+4)(x-1)) ?

The solution to expand (x^2-10x-41)/((x+1)(x+4)(x-1)) is (x^2-10x-41)/(x^3+4x^2-x-4)

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expand (x^2-10x-41)/((x+1)(x+4)(x-1))

expand

\frac{x ^{2} - 10 x - 41}{( x + 1 ) ( x + 4 ) ( x - 1 )}

\frac{x ^{2} - 10 x - 41}{x ^{3} + 4 x ^{2} - x - 4}

Solution steps

\frac{x ^{2} - 10 x - 41}{( x + 1 ) ( x + 4 ) ( x - 1 )}

Expand

(x + 1) (x + 4) (x - 1) : x^{3} + 4 x^{2} - x - 4

= \frac{x ^{2} - 10 x - 41}{x ^{3} + 4 x ^{2} - x - 4}

π (16 x^{2} + 24 x + 9)

\frac{5 ( x - 1 ) ^{4} ( x ^{2} + x + 1 ) ^{4} ( x ^{3} + 2 )}{x ^{11}}

(- 1 + i)^{17}

(x - 2) (x + 1 - 2 i) (x + 1 + 2 i)

lo g_{3} (\frac{x}{z})

What is expand (x^2-10x-41)/((x+1)(x+4)(x-1)) ?
The solution to expand (x^2-10x-41)/((x+1)(x+4)(x-1)) is (x^2-10x-41)/(x^3+4x^2-x-4)