What is expand (2rcos(θ)-rsin(θ))r ?

The solution to expand (2rcos(θ)-rsin(θ))r is 2r^2cos(θ)-r^2sin(θ)

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expand (2rcos(θ)-rsin(θ))r

expand

(2 r cos (θ) - r sin (θ)) r

2 r^{2} cos (θ) - r^{2} sin (θ)

Solution steps

(2 r cos (θ) - r sin (θ)) r

= r (2 r cos (θ) - r sin (θ))

Apply the distributive law:

a (b - c) = ab - a c

r (2 r cos (θ) - r sin (θ)) = r \cdot 2 r cos (θ) - rr sin (θ)

= r \cdot 2 r cos (θ) - rr sin (θ)

Simplify

r \cdot 2 r cos (θ) - rr sin (θ) : 2 r^{2} cos (θ) - r^{2} sin (θ)

= 2 r^{2} cos (θ) - r^{2} sin (θ)

\frac{2 s ^{2} + 2 s + 1}{s ^{3} ( s + 1 )}

\frac{( e ^{\frac{y}{t}} )}{( e ^{\frac{y}{t}} ) ^{2}}

(x + z) (sin (t))

(x + 2) e^{3}

\frac{a ^{2} + 9 x + 20}{( a + 4 ) ( a + 5 )}

What is expand (2rcos(θ)-rsin(θ))r ?
The solution to expand (2rcos(θ)-rsin(θ))r is 2r^2cos(θ)-r^2sin(θ)