What is expand (2x+cos(x))(3-e^x) ?

The solution to expand (2x+cos(x))(3-e^x) is 6x-2e^xx+3cos(x)-e^xcos(x)

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expand (2x+cos(x))(3-e^x)

expand

(2 x + cos (x)) (3 - e^{x})

6 x - 2 e^{x} x + 3 cos (x) - e^{x} cos (x)

Solution steps

(2 x + cos (x)) (3 - e^{x})

Apply FOIL method:

(a + b) (c + d) = a c + a d + b c + b d

a = 2 x, b = cos (x), c = 3, d = - e^{x}

= 2 x \cdot 3 + 2 x (- e^{x}) + cos (x) \cdot 3 + cos (x) (- e^{x})

Apply minus-plus rules

+ (- a) = - a

= 2 \cdot 3 x - 2 e^{x} x + 3 cos (x) - e^{x} cos (x)

Multiply the numbers:

2 \cdot 3 = 6

= 6 x - 2 e^{x} x + 3 cos (x) - e^{x} cos (x)

\frac{( 4 e ^{x} ( 4 - e ^{x} ) )}{( 4 + e ^{x} ) ^{3}}

(\frac{1}{t} - i)^{2}

ln (x^{2} + 1) + (sin (x) + 5)^{4}

\frac{8 ( 6 6 - 5 5 )}{3} - 9

(2 + 32) \cdot 41

What is expand (2x+cos(x))(3-e^x) ?
The solution to expand (2x+cos(x))(3-e^x) is 6x-2e^xx+3cos(x)-e^xcos(x)