What is x(1-x)(f\circ g)x(1-x) ?

The solution to x(1-x)(f\circ g)x(1-x) is \circ x^2fg(1-x)^2

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simplify x(1-x)(f\circ g)x(1-x)

simplify

x (1 - x) (f \circ g) x (1 - x)

\circ x^{2} f g (1 - x)^{2}

Solution steps

x (1 - x) (f \circ g) x (1 - x)

Remove parentheses:

(a) = a

= x (1 - x) f \circ gx (1 - x)

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

(1 - x) (1 - x) = (1 - x)^{1 + 1}

= x f \circ gx (1 - x)^{1 + 1}

Add the numbers:

1 + 1 = 2

= x f \circ gx (1 - x)^{2}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

xx = x^{1 + 1}

= f \circ g x^{1 + 1} (1 - x)^{2}

Add the numbers:

1 + 1 = 2

= f \circ g x^{2} (1 - x)^{2}

(x y^{2} + x) d x + y x^{2} d y

(2 c t + b) t

sin^{2} (x) - cos (x) \cdot (sin (x) - cos (x))

(e^{5 x}) \cdot (e^{5 x} + 5 x e^{5 x})

(1 + \frac{2}{5} x)^{5}

What is x(1-x)(f\circ g)x(1-x) ?
The solution to x(1-x)(f\circ g)x(1-x) is \circ x^2fg(1-x)^2