What is expand ((x+1)(x-6))/(2(x+2)(x-3)) ?

The solution to expand ((x+1)(x-6))/(2(x+2)(x-3)) is (x^2-5x-6)/(2x^2-2x-12)

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expand ((x+1)(x-6))/(2(x+2)(x-3))

expand

\frac{( x + 1 ) ( x - 6 )}{2 ( x + 2 ) ( x - 3 )}

\frac{x ^{2} - 5 x - 6}{2 x ^{2} - 2 x - 12}

Solution steps

\frac{( x + 1 ) ( x - 6 )}{2 ( x + 2 ) ( x - 3 )}

Expand

2 (x + 2) (x - 3) : 2 x^{2} - 2 x - 12

= \frac{( x + 1 ) ( x - 6 )}{2 x ^{2} - 2 x - 12}

Expand

(x + 1) (x - 6) : x^{2} - 5 x - 6

= \frac{x ^{2} - 5 x - 6}{2 x ^{2} - 2 x - 12}

cos (x) (x + y)

(\frac{3 x ^{2}}{2} - \frac{1}{3 x})^{15}

5 (1 - e^{- \frac{t}{2}})

\frac{1011.6}{( x + 1 ) ^{4}}

3 (2 w + 5 = 33)

What is expand ((x+1)(x-6))/(2(x+2)(x-3)) ?
The solution to expand ((x+1)(x-6))/(2(x+2)(x-3)) is (x^2-5x-6)/(2x^2-2x-12)