What is expand x^{1/3}(x^2+4) ?

The solution to expand x^{1/3}(x^2+4) is x^{7/3}+x^{1/3}*4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand x^{1/3}(x^2+4)

expand

x^{\frac{1}{3}} (x^{2} + 4)

x^{\frac{7}{3}} + x^{\frac{1}{3}} \cdot 4

Solution steps

x^{\frac{1}{3}} (x^{2} + 4)

Apply the distributive law:

a (b + c) = ab + a c

x^{\frac{1}{3}} (x^{2} + 4) = x^{\frac{1}{3}} x^{2} + x^{\frac{1}{3}} \cdot 4

= x^{\frac{1}{3}} x^{2} + x^{\frac{1}{3}} \cdot 4

Simplify

x^{\frac{1}{3}} x^{2} : x^{\frac{7}{3}}

= x^{\frac{7}{3}} + x^{\frac{1}{3}} \cdot 4

(2 x + 1) \cdot ln (2 x + 1)

- sin (x) \cdot (6 (2 x + 1)^{2})

(4 x^{2} - 5 y^{2} + x) d x + x y d y

2 (x + Δ x)^{2} - 3

x (3 x - 2)

What is expand x^{1/3}(x^2+4) ?
The solution to expand x^{1/3}(x^2+4) is x^{7/3}+x^{1/3}*4