What is expand 1/((s-θ+iv)(s-θ-iv)) ?

The solution to expand 1/((s-θ+iv)(s-θ-iv)) is 1/((s-θ)^2+v^2)

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expand 1/((s-θ+iv)(s-θ-iv))

expand

\frac{1}{( s - θ + i v ) ( s - θ - i v )}

\frac{1}{( s - θ ) ^{2} + v ^{2}}

Solution steps

\frac{1}{( s - θ + i v ) ( s - θ - i v )}

(s - θ + i v) (s - θ - i v) : (s - θ)^{2} + v^{2}

= \frac{1}{( s - θ ) ^{2} + v ^{2}}

(1 + x + 1)^{2}

(x + 26) (x - 26)

\frac{2 - 3 x ^{2} - y ^{2}}{( x + y ) ^{2}}

(x^{6} y^{6}) (x^{11} y^{10})

(x - 3 - 1) (x - 3 + 1)

What is expand 1/((s-θ+iv)(s-θ-iv)) ?
The solution to expand 1/((s-θ+iv)(s-θ-iv)) is 1/((s-θ)^2+v^2)