What is expand-10e^{-2t}+10(t+1)e^{-3t} ?

The solution to expand-10e^{-2t}+10(t+1)e^{-3t} is -10e^{-2t}+10e^{-3t}t+10e^{-3t}

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expand-10e^{-2t}+10(t+1)e^{-3t}

expand

- 10 e^{- 2 t} + 10 (t + 1) e^{- 3 t}

- 10 e^{- 2 t} + 10 e^{- 3 t} t + 10 e^{- 3 t}

Solution steps

- 10 e^{- 2 t} + 10 (t + 1) e^{- 3 t}

= - 10 e^{- 2 t} + 10 e^{- 3 t} (t + 1)

Expand

10 e^{- 3 t} (t + 1) : 10 e^{- 3 t} t + 10 e^{- 3 t}

= - 10 e^{- 2 t} + 10 e^{- 3 t} t + 10 e^{- 3 t}

(\frac{4}{s} - \frac{1}{s ^{3}})^{2}

\frac{1}{( t + t ^{2} ) ^{13}}

48 (3 - 5)

\frac{1}{tan ^{2} ( x )} + 1 \cdot sec (x)

4 (3 - 2)

What is expand-10e^{-2t}+10(t+1)e^{-3t} ?
The solution to expand-10e^{-2t}+10(t+1)e^{-3t} is -10e^{-2t}+10e^{-3t}t+10e^{-3t}