What is expand 5/2 (2/5 x+y=7) ?

The solution to expand 5/2 (2/5 x+y=7) is x+(5y)/2 =7

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expand 5/2 (2/5 x+y=7)

expand

\frac{5}{2} (\frac{2}{5} x + y = 7)

x + \frac{5 y}{2} = 7

Solution steps

\frac{5}{2} (\frac{2}{5} x + y = 7)

= \frac{5}{2} (\frac{2}{5} x + 7 = y)

Apply the distributive law:

a (b + c) = ab + a c

a = \frac{5}{2}, b = \frac{2}{5} x, c = y = 7

\frac{5}{2} \cdot \frac{2}{5} x + \frac{5}{2} y = 7

Expand

\frac{5}{2} \cdot \frac{2}{5} x + \frac{5}{2} y : x + \frac{5 y}{2}

x + \frac{5 y}{2} = 7

2 sec^{5} (x) sin (x) (1 + sin^{2} (x))

(k + 1) (\frac{1}{2} + \frac{1}{4})

(x - 7) (x + 2 + 3)

2 x (1 - x^{\frac{1}{2}})

12 x^{12 x} (ln (x) + 1) \cdot (sin^{6 x} (x))

What is expand 5/2 (2/5 x+y=7) ?
The solution to expand 5/2 (2/5 x+y=7) is x+(5y)/2 =7