What is expand (2x^3-3x^2+4x)/((2x^2-3)) ?

The solution to expand (2x^3-3x^2+4x)/((2x^2-3)) is (2x^3-3x^2+4x)/(2x^2-3)

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expand (2x^3-3x^2+4x)/((2x^2-3))

expand

\frac{2 x ^{3} - 3 x ^{2} + 4 x}{( 2 x ^{2} - 3 )}

\frac{2 x ^{3} - 3 x ^{2} + 4 x}{2 x ^{2} - 3}

Solution steps

\frac{2 x ^{3} - 3 x ^{2} + 4 x}{( 2 x ^{2} - 3 )}

Remove parentheses:

(a) = a

= \frac{2 x ^{3} - 3 x ^{2} + 4 x}{2 x ^{2} - 3}

(a - a^{2} - 1)^{3}

(a - a^{2} - 1)^{2}

\frac{x - x ln ( x )}{2} \cdot (- x)

(- 10 - 35) (7 + 821)

What is expand (2x^3-3x^2+4x)/((2x^2-3)) ?
The solution to expand (2x^3-3x^2+4x)/((2x^2-3)) is (2x^3-3x^2+4x)/(2x^2-3)