What is expand (2x^2-2x-4)/((2x-1)^2) ?

The solution to expand (2x^2-2x-4)/((2x-1)^2) is (2x^2-2x-4)/(4x^2-4x+1)

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expand (2x^2-2x-4)/((2x-1)^2)

expand

\frac{2 x ^{2} - 2 x - 4}{( 2 x - 1 ) ^{2}}

\frac{2 x ^{2} - 2 x - 4}{4 x ^{2} - 4 x + 1}

Solution steps

\frac{2 x ^{2} - 2 x - 4}{( 2 x - 1 ) ^{2}}

(2 x - 1)^{2} = 4 x^{2} - 4 x + 1

= \frac{2 x ^{2} - 2 x - 4}{4 x ^{2} - 4 x + 1}

\frac{3}{4} (x + \frac{1}{2} sin (2 x))

f or (x^{4} + 20 - \frac{x ^{4}}{12})

\frac{918 x ^{2} - 21 x - 124}{2 ( 6 x ^{2} - 5 x + 4 ) ( 9 x + 4 )}

(5 + h) - 5

What is expand (2x^2-2x-4)/((2x-1)^2) ?
The solution to expand (2x^2-2x-4)/((2x-1)^2) is (2x^2-2x-4)/(4x^2-4x+1)