What is expand 2(e^xcos(x)-e^xsin(x)) ?

The solution to expand 2(e^xcos(x)-e^xsin(x)) is 2e^xcos(x)-2e^xsin(x)

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expand 2(e^xcos(x)-e^xsin(x))

expand

2 (e^{x} cos (x) - e^{x} sin (x))

2 e^{x} cos (x) - 2 e^{x} sin (x)

Solution steps

2 (e^{x} cos (x) - e^{x} sin (x))

Apply the distributive law:

a (b - c) = ab - a c

a = 2, b = e^{x} cos (x), c = e^{x} sin (x)

= 2 e^{x} cos (x) - 2 e^{x} sin (x)

\frac{( x - 1 ) ( x ^{3} - x ^{2} - 4 x - 4 )}{x - 3}

\frac{2 ( - 8 x y ^{4} + 6 y ^{3} )}{( 1 - 2 x y ) ^{3}}

\frac{2 x ^{3} - x + 5}{2 ( x + 1 ) ( 2 x - 1 )}

(- x + 5 + 4)^{2}

(z + 20 i)^{2}

What is expand 2(e^xcos(x)-e^xsin(x)) ?
The solution to expand 2(e^xcos(x)-e^xsin(x)) is 2e^xcos(x)-2e^xsin(x)