What is (z-1/6)(z+1/6) ?

The solution to (z-1/6)(z+1/6) is ((6z-1)(6z+1))/(36)

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simplify (z-1/6)(z+1/6)

simplify

(z - \frac{1}{6}) (z + \frac{1}{6})

\frac{( 6 z - 1 ) ( 6 z + 1 )}{36}

Solution steps

(z - \frac{1}{6}) (z + \frac{1}{6})

Simplify

z - \frac{1}{6} : \frac{6 z - 1}{6}

= \frac{6 z - 1}{6} (z + \frac{1}{6})

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 6 z - 1 ) ( z + \frac{1}{6} )}{6}

Simplify

(6 z - 1) (z + \frac{1}{6}) : \frac{( 6 z - 1 ) ( z \cdot 6 + 1 )}{6}

= \frac{\frac{( 6 z - 1 ) ( z \cdot 6 + 1 )}{6}}{6}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{( 6 z - 1 ) ( z \cdot 6 + 1 )}{6 \cdot 6}

Multiply the numbers:

6 \cdot 6 = 36

= \frac{( 6 z - 1 ) ( z \cdot 6 + 1 )}{36}

= \frac{( 6 z - 1 ) ( 6 z + 1 )}{36}

\frac{22}{( x - 1 ) ( x + 1 )}

\frac{1}{10} - \frac{1}{200} (0.98 - 1) - \frac{3}{50} (3.04 - 3)

10 (8 x - 9 y = 13)

u (t - π) sin (t)

\frac{6}{( s - 1 ) ^{4}}