What is expand 2/3 (2x-1+(-(3x+2))= 5/2 (3x-5)) ?

The solution to expand 2/3 (2x-1+(-(3x+2))= 5/2 (3x-5)) is -(2x)/3-2=(15x)/2-25/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand 2/3 (2x-1+(-(3x+2))= 5/2 (3x-5))

expand

\frac{2}{3} (2 x - 1 + (- (3 x + 2)) = \frac{5}{2} (3 x - 5))

- \frac{2 x}{3} - 2 = \frac{15 x}{2} - \frac{25}{2}

Solution steps

\frac{2}{3} (2 x - 1 + (- (3 x + 2)) = \frac{5}{2} (3 x - 5))

= \frac{2}{3} (2 x - 1 + \frac{5}{2} = (- (3 x + 2)) (3 x - 5))

Distribute parentheses

\frac{2}{3} \cdot 2 x + \frac{2}{3} (- 1) + \frac{2}{3} (- (3 x + 2)) = \frac{5}{2} (3 x - 5)

Apply minus-plus rules

+ (- a) = - a

2 \cdot \frac{2}{3} x - 1 \cdot \frac{2}{3} + \frac{2}{3} (- (3 x + 2)) = \frac{5}{2} (3 x - 5)

Simplify

2 \cdot \frac{2}{3} x - 1 \cdot \frac{2}{3} + \frac{2}{3} (- (3 x + 2)) = \frac{5}{2} (3 x - 5) : - \frac{2 x}{3} - 2 = \frac{15 x}{2} - \frac{25}{2}

- \frac{2 x}{3} - 2 = \frac{15 x}{2} - \frac{25}{2}

100 (569 + 39)

\frac{x}{4 ( x + 8 )}

, (0.375 x) (60 x - \frac{3 x ^{2}}{2})

16 (4 - π)

(7 x^{2} + 5 x - 2)^{8}

What is expand 2/3 (2x-1+(-(3x+2))= 5/2 (3x-5)) ?
The solution to expand 2/3 (2x-1+(-(3x+2))= 5/2 (3x-5)) is -(2x)/3-2=(15x)/2-25/2