What is expand (7x-3)/(x(x+3)(x-1)) ?

The solution to expand (7x-3)/(x(x+3)(x-1)) is (7x-3)/(x^3+2x^2-3x)

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expand (7x-3)/(x(x+3)(x-1))

expand

\frac{7 x - 3}{x ( x + 3 ) ( x - 1 )}

\frac{7 x - 3}{x ^{3} + 2 x ^{2} - 3 x}

Solution steps

\frac{7 x - 3}{x ( x + 3 ) ( x - 1 )}

Expand

x (x + 3) (x - 1) : x^{3} + 2 x^{2} - 3 x

= \frac{7 x - 3}{x ^{3} + 2 x ^{2} - 3 x}

(4 + x) (5 + x)

(i w + 1)^{3}

\frac{( x + 6 ) ^{2}}{x + 8}

\frac{1}{( x + 1 ) ( x ^{2} + 1 ) ^{2}}

(x^{2} - 2) y d x

What is expand (7x-3)/(x(x+3)(x-1)) ?
The solution to expand (7x-3)/(x(x+3)(x-1)) is (7x-3)/(x^3+2x^2-3x)