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Popular >

expand ((3p-2)^2)/9

Solution

expand

\frac{( 3 p - 2 ) ^{2}}{9}

Solution

p^{2} - \frac{4 p}{3} + \frac{4}{9}

Solution steps

\frac{( 3 p - 2 ) ^{2}}{9}

(3 p - 2)^{2} = 9 p^{2} - 12 p + 4

= \frac{9 p ^{2} - 12 p + 4}{9}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{9 p ^{2} - 12 p + 4}{9} = \frac{9 p ^{2}}{9} - \frac{12 p}{9} + \frac{4}{9}

= \frac{9 p ^{2}}{9} - \frac{12 p}{9} + \frac{4}{9}

Divide the numbers:

\frac{9}{9} = 1

= p^{2} - \frac{12 p}{9} + \frac{4}{9}

Cancel

\frac{12 p}{9} : \frac{4 p}{3}

= p^{2} - \frac{4 p}{3} + \frac{4}{9}

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Frequently Asked Questions (FAQ)

What is expand ((3p-2)^2)/9 ?
The solution to expand ((3p-2)^2)/9 is p^2-(4p)/3+4/9