What is expand (3(x-1)(x-2)(x+1))/2 ?

The solution to expand (3(x-1)(x-2)(x+1))/2 is (3x^3)/2-3x^2-(3x)/2+3

Popular >

expand (3(x-1)(x-2)(x+1))/2

expand

\frac{3 ( x - 1 ) ( x - 2 ) ( x + 1 )}{2}

\frac{3 x ^{3}}{2} - 3 x^{2} - \frac{3 x}{2} + 3

Solution steps

\frac{3 ( x - 1 ) ( x - 2 ) ( x + 1 )}{2}

Expand

3 (x - 1) (x - 2) (x + 1) : 3 x^{3} - 6 x^{2} - 3 x + 6

= \frac{3 x ^{3} - 6 x ^{2} - 3 x + 6}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{3 x ^{3} - 6 x ^{2} - 3 x + 6}{2} = \frac{3 x ^{3}}{2} - \frac{6 x ^{2}}{2} - \frac{3 x}{2} + \frac{6}{2}

= \frac{3 x ^{3}}{2} - \frac{6 x ^{2}}{2} - \frac{3 x}{2} + \frac{6}{2}

Divide the numbers:

\frac{6}{2} = 3

= \frac{3 x ^{3}}{2} - 3 x^{2} - \frac{3 x}{2} + 3

c (n, r - 1)

\frac{1}{4 ( e ^{x} - e ^{- x} ) ^{2}}

lo g_{10} (x y)

(2 x^{5} + 5 x^{4}) ln (7 x^{5})

\frac{\partial}{\partial x} ((y) (x^{2} + 6 x y + y^{3}))

What is expand (3(x-1)(x-2)(x+1))/2 ?
The solution to expand (3(x-1)(x-2)(x+1))/2 is (3x^3)/2-3x^2-(3x)/2+3