What is the answer to solvefor j,m=4i-7j-k^0 ?

The answer to solvefor j,m=4i-7j-k^0 is j=(-1-m)/7+i 4/7

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solvefor j,m=4i-7j-k^0

solve for

j, m = 4 i - 7 j - k^{0}

j = \frac{- 1 - m}{7} + i \frac{4}{7}

Solution steps

m = 4 i - 7 j - k^{0}

Switch sides

4 i - 7 j - k^{0} = m

Apply rule

a^{0} = 1, a \neq = 0

k^{0} = 1

4 i - 7 j - 1 = m

Move

4 i

to the right side

- 7 j - 1 = m - 4 i

Move

1

to the right side

- 7 j = m - 4 i + 1

Divide both sides by

- 7

j = \frac{- 1 - m}{7} + i \frac{4}{7}

k e^{8 (k + 1)}

(15 + j^{37.89}) x - (j^{37}, 89) y

f (s) = \frac{1}{s e ^{3 (s - 1)}}

5 (x - \frac{1}{10})^{2} + \frac{9}{400}

(0.5 + u)^{3}

What is the answer to solvefor j,m=4i-7j-k^0 ?
The answer to solvefor j,m=4i-7j-k^0 is j=(-1-m)/7+i 4/7