What is expand (1/2 m^x-6n^y)^2 ?

The solution to expand (1/2 m^x-6n^y)^2 is 1/4 m^{2x}-6m^xn^y+36n^{2y}

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expand (1/2 m^x-6n^y)^2

expand

(\frac{1}{2} m^{x} - 6 n^{y})^{2}

\frac{1}{4} m^{2 x} - 6 m^{x} n^{y} + 36 n^{2 y}

Solution steps

(\frac{1}{2} m^{x} - 6 n^{y})^{2}

Apply Perfect Square Formula:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

(\frac{1}{2} m^{x} - 6 n^{y})^{2} = (\frac{1}{2} m^{x})^{2} - 2 \cdot \frac{1}{2} m^{x} \cdot 6 n^{y} + (6 n^{y})^{2}

= (\frac{1}{2} m^{x})^{2} - 2 \cdot \frac{1}{2} m^{x} \cdot 6 n^{y} + (6 n^{y})^{2}

Simplify

(\frac{1}{2} m^{x})^{2} - 2 \cdot \frac{1}{2} m^{x} \cdot 6 n^{y} + (6 n^{y})^{2} : \frac{1}{4} m^{2 x} - 6 m^{x} n^{y} + 36 n^{2 y}

= \frac{1}{4} m^{2 x} - 6 m^{x} n^{y} + 36 n^{2 y}

(x^{2} + \frac{5}{49}) (x^{2} - 4 x + 4)

- \frac{2 sec ^{2} ( x )}{( 1 + tan ( x ) ) ^{3}}

(v y - y) (v d y + y d v)

\frac{4 !}{3 ! \cdot ( 1 - ( 1 - x ) ) ^{3} \cdot ( 1 - ( 1 - x ) ) ^{1}}

What is expand (1/2 m^x-6n^y)^2 ?
The solution to expand (1/2 m^x-6n^y)^2 is 1/4 m^{2x}-6m^xn^y+36n^{2y}