What is (z+3/2)(z-3/2) ?

The solution to (z+3/2)(z-3/2) is ((2z+3)(2z-3))/4

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simplify (z+3/2)(z-3/2)

simplify

(z + \frac{3}{2}) (z - \frac{3}{2})

\frac{( 2 z + 3 ) ( 2 z - 3 )}{4}

Solution steps

(z + \frac{3}{2}) (z - \frac{3}{2})

Simplify

z + \frac{3}{2} : \frac{2 z + 3}{2}

= \frac{2 z + 3}{2} (z - \frac{3}{2})

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 2 z + 3 ) ( z - \frac{3}{2} )}{2}

Simplify

(2 z + 3) (z - \frac{3}{2}) : \frac{( 2 z + 3 ) ( z \cdot 2 - 3 )}{2}

= \frac{\frac{( 2 z + 3 ) ( z \cdot 2 - 3 )}{2}}{2}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{( 2 z + 3 ) ( z \cdot 2 - 3 )}{2 \cdot 2}

Multiply the numbers:

2 \cdot 2 = 4

= \frac{( 2 z + 3 ) ( z \cdot 2 - 3 )}{4}

= \frac{( 2 z + 3 ) ( 2 z - 3 )}{4}

(1 - cos (8 x))^{3}

\frac{x}{( x ^{2} + 2 ) ^{2}}

5 (5 + 7)

4 (5 - 1)

2 (- 5.555 + 2 y = - 7)