What is expand (16)/(x^2\times (x-4)) ?

The solution to expand (16)/(x^2\times (x-4)) is (16)/(x^3-4x^2)

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expand (16)/(x^2\times (x-4))

expand

\frac{16}{x ^{2} \cdot ( x - 4 )}

\frac{16}{x ^{3} - 4 x ^{2}}

Solution steps

\frac{16}{x ^{2} ( x - 4 )}

Expand

x^{2} (x - 4) : x^{3} - 4 x^{2}

= \frac{16}{x ^{3} - 4 x ^{2}}

\frac{( 4 x - 2 x ^{2} )}{( 1 + x ) ^{2}}

\frac{( 4 x - 1 )}{( x + 2 ) ( x - 1 ) ^{2}}

e \cdot (- \frac{1}{x} + 1)

\frac{( x + 8 )}{( 4 - 3 x ) ^{\frac{1}{2}}}

(x + 1)^{4} y^{''} (x) + 2 (x + 1)^{3} y^{'} (x)

What is expand (16)/(x^2\times (x-4)) ?
The solution to expand (16)/(x^2\times (x-4)) is (16)/(x^3-4x^2)