What is expand (z^2cos(y)e^x)(x-1) ?

The solution to expand (z^2cos(y)e^x)(x-1) is e^xz^2xcos(y)-e^xz^2cos(y)

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expand (z^2cos(y)e^x)(x-1)

expand

(z^{2} cos (y) e^{x}) (x - 1)

e^{x} z^{2} x cos (y) - e^{x} z^{2} cos (y)

Solution steps

(z^{2} cos (y) e^{x}) (x - 1)

= (e^{x} z^{2} cos (y)) (x - 1)

Apply the distributive law:

a (b - c) = ab - a c

a = (z^{2} cos (y) e^{x}), b = x, c = 1

= (z^{2} cos (y) e^{x}) x - (z^{2} cos (y) e^{x}) \cdot 1

= x (e^{x} z^{2} cos (y)) - 1 \cdot (e^{x} z^{2} cos (y))

Simplify

x (e^{x} z^{2} cos (y)) - 1 \cdot (e^{x} z^{2} cos (y)) : e^{x} z^{2} x cos (y) - e^{x} z^{2} cos (y)

= e^{x} z^{2} x cos (y) - e^{x} z^{2} cos (y)

9 (3 - 4 cos (2 x) + cos (4 x))

\frac{( n - v ) ^{2}}{v}

\frac{π ( e ^{2} + 5 )}{2} - 2 π e

(2 x + y) \cdot (x + \frac{y}{x})^{5}

(x^{- 2})^{2}

What is expand (z^2cos(y)e^x)(x-1) ?
The solution to expand (z^2cos(y)e^x)(x-1) is e^xz^2xcos(y)-e^xz^2cos(y)