What is expand (2x^3-x+4)/((x+1)(x^2-4)^2) ?

The solution to expand (2x^3-x+4)/((x+1)(x^2-4)^2) is (2x^3-x+4)/(x^5-8x^3+16x+x^4-8x^2+16)

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expand (2x^3-x+4)/((x+1)(x^2-4)^2)

expand

\frac{2 x ^{3} - x + 4}{( x + 1 ) ( x ^{2} - 4 ) ^{2}}

\frac{2 x ^{3} - x + 4}{x ^{5} - 8 x ^{3} + 16 x + x ^{4} - 8 x ^{2} + 16}

Solution steps

\frac{2 x ^{3} - x + 4}{( x + 1 ) ( x ^{2} - 4 ) ^{2}}

(x^{2} - 4)^{2} = x^{4} - 8 x^{2} + 16

= \frac{2 x ^{3} - x + 4}{( x + 1 ) ( x ^{4} - 8 x ^{2} + 16 )}

Expand

(x + 1) (x^{4} - 8 x^{2} + 16) : x^{5} - 8 x^{3} + 16 x + x^{4} - 8 x^{2} + 16

= \frac{2 x ^{3} - x + 4}{x ^{5} - 8 x ^{3} + 16 x + x ^{4} - 8 x ^{2} + 16}

A (3, 2, - 4) B (- 5, 4, 4)

(e^{2 x} - e^{x})^{2}

\frac{4 s ^{2} + 36 + s ^{3} + 16 s}{( s ^{2} + 9 ) ( s ^{2} + 16 )}

\frac{1}{3 \cdot x ( x - 8 )}

What is expand (2x^3-x+4)/((x+1)(x^2-4)^2) ?
The solution to expand (2x^3-x+4)/((x+1)(x^2-4)^2) is (2x^3-x+4)/(x^5-8x^3+16x+x^4-8x^2+16)