What is expand (2Ax+B)e^{3x}+e^{3x}*3(Ax^2+Bx) ?

The solution to expand (2Ax+B)e^{3x}+e^{3x}*3(Ax^2+Bx) is 2Ae^{3x}x+Be^{3x}+3Ae^{3x}x^2+3Be^{3x}x

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expand (2Ax+B)e^{3x}+e^{3x}*3(Ax^2+Bx)

expand

(2 A x + B) e^{3 x} + e^{3 x} \cdot 3 (A x^{2} + B x)

2 A e^{3 x} x + B e^{3 x} + 3 A e^{3 x} x^{2} + 3 B e^{3 x} x

Solution steps

(2 A x + B) e^{3 x} + e^{3 x} \cdot 3 (A x^{2} + B x)

= e^{3 x} (2 A x + B) + 3 e^{3 x} (A x^{2} + B x)

Expand

e^{3 x} (2 A x + B) : 2 A e^{3 x} x + B e^{3 x}

= 2 A e^{3 x} x + B e^{3 x} + e^{3 x} \cdot 3 (A x^{2} + B x)

Expand

e^{3 x} \cdot 3 (A x^{2} + B x) : 3 A e^{3 x} x^{2} + 3 B e^{3 x} x

= 2 A e^{3 x} x + B e^{3 x} + 3 A e^{3 x} x^{2} + 3 B e^{3 x} x

(x - 4 - 2) (x + 4 + 2)

\frac{x ( ln ( x ) ) ^{2}}{( x + 1 ) ( ln ( x + 1 ) ) ^{2}}

\frac{( ( 1 - 3 y ) ^{2} )}{x}

(3 - x) \times (1 - x)

((s cos (t)) + (t)) (s cos (t))

What is expand (2Ax+B)e^{3x}+e^{3x}*3(Ax^2+Bx) ?
The solution to expand (2Ax+B)e^{3x}+e^{3x}*3(Ax^2+Bx) is 2Ae^{3x}x+Be^{3x}+3Ae^{3x}x^2+3Be^{3x}x