What is expand (3x^2+4x)/(2(x+1)^{3/2)} ?

The solution to expand (3x^2+4x)/(2(x+1)^{3/2)} is (3x^2)/(2(x+1)^{3/2)}+(2x)/((x+1)^{3/2)}

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expand (3x^2+4x)/(2(x+1)^{3/2)}

expand

\frac{3 x ^{2} + 4 x}{2 ( x + 1 ) ^{\frac{3}{2}}}

\frac{3 x ^{2}}{2 ( x + 1 ) ^{\frac{3}{2}}} + \frac{2 x}{( x + 1 ) ^{\frac{3}{2}}}

Solution steps

\frac{3 x ^{2} + 4 x}{2 ( x + 1 ) ^{\frac{3}{2}}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{3 x ^{2} + 4 x}{2 ( x + 1 ) ^{\frac{3}{2}}} = \frac{3 x ^{2}}{2 ( x + 1 ) ^{\frac{3}{2}}} + \frac{4 x}{2 ( x + 1 ) ^{\frac{3}{2}}}

= \frac{3 x ^{2}}{2 ( x + 1 ) ^{\frac{3}{2}}} + \frac{4 x}{2 ( x + 1 ) ^{\frac{3}{2}}}

Divide the numbers:

\frac{4}{2} = 2

= \frac{3 x ^{2}}{2 ( x + 1 ) ^{\frac{3}{2}}} + \frac{2 x}{( x + 1 ) ^{\frac{3}{2}}}

s t e p (t - 2)

(1 - 2 \cdot π \cdot i \cdot n)^{2}

(4 + 9 x^{2}) d y - 9 - 4 y^{2}

(x + 1 - \frac{9}{x - 1}) \cdot 2

(x + 1) (x - \frac{1}{3})

What is expand (3x^2+4x)/(2(x+1)^{3/2)} ?
The solution to expand (3x^2+4x)/(2(x+1)^{3/2)} is (3x^2)/(2(x+1)^{3/2)}+(2x)/((x+1)^{3/2)}