What is h(1-(v^2t^2)/(b^2)) ?

The solution to h(1-(v^2t^2)/(b^2)) is (h(b^2-v^2t^2))/(b^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify h(1-(v^2t^2)/(b^2))

simplify

h (1 - \frac{v ^{2} t ^{2}}{b ^{2}})

\frac{h ( b ^{2} - v ^{2} t ^{2} )}{b ^{2}}

Solution steps

h (1 - \frac{v ^{2} t ^{2}}{b ^{2}})

Join

1 - \frac{v ^{2} t ^{2}}{b ^{2}} : \frac{b ^{2} - v ^{2} t ^{2}}{b ^{2}}

= h \frac{b ^{2} - v ^{2} t ^{2}}{b ^{2}}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{h ( b ^{2} - v ^{2} t ^{2} )}{b ^{2}}

\frac{s ^{3}}{( π ^{2} + s ^{2} ) ( s - φ )}

δ (x - 40 π)

(1 + x^{\frac{3}{4}}) (1 - x^{\frac{2}{3}})

(x + y - x - y)^{2}

What is h(1-(v^2t^2)/(b^2)) ?
The solution to h(1-(v^2t^2)/(b^2)) is (h(b^2-v^2t^2))/(b^2)