What is expand (e^{3x}+3e^{3x}x)e^{3x} ?

The solution to expand (e^{3x}+3e^{3x}x)e^{3x} is e^{6x}+3e^{6x}x

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expand (e^{3x}+3e^{3x}x)e^{3x}

expand

(e^{3 x} + 3 e^{3 x} x) e^{3 x}

e^{6 x} + 3 e^{6 x} x

Solution steps

(e^{3 x} + 3 e^{3 x} x) e^{3 x}

= e^{3 x} (e^{3 x} + 3 e^{3 x} x)

Apply the distributive law:

a (b + c) = ab + a c

a = e^{3 x}, b = e^{3 x}, c = 3 e^{3 x} x

= e^{3 x} e^{3 x} + e^{3 x} \cdot 3 e^{3 x} x

= e^{3 x} e^{3 x} + 3 e^{3 x} e^{3 x} x

Simplify

e^{3 x} e^{3 x} + 3 e^{3 x} e^{3 x} x : e^{6 x} + 3 e^{6 x} x

= e^{6 x} + 3 e^{6 x} x

(x + 1) (x - \frac{1}{2})

\frac{s - 6}{( s ^{2} - 1 ) ( s ^{2} + 4 )}

sin (6) (2 e^{5 x^{4}} x + 20 e^{5 x^{4}} x^{5})

\frac{x}{( x + 3 ) ( x + 1 )}

\frac{1}{2} + \frac{3}{32} (4 \cdot 1.1 - \frac{1. 1 ^{3}}{3})

What is expand (e^{3x}+3e^{3x}x)e^{3x} ?
The solution to expand (e^{3x}+3e^{3x}x)e^{3x} is e^{6x}+3e^{6x}x