What is expand (2(2v^3-11v^2+22v-15))/(2x-3) ?

The solution to expand (2(2v^3-11v^2+22v-15))/(2x-3) is (4v^3-22v^2+44v-30)/(2x-3)

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expand (2(2v^3-11v^2+22v-15))/(2x-3)

expand

\frac{2 ( 2 v ^{3} - 11 v ^{2} + 22 v - 15 )}{2 x - 3}

\frac{4 v ^{3} - 22 v ^{2} + 44 v - 30}{2 x - 3}

Solution steps

\frac{2 ( 2 v ^{3} - 11 v ^{2} + 22 v - 15 )}{2 x - 3}

Expand

2 (2 v^{3} - 11 v^{2} + 22 v - 15) : 4 v^{3} - 22 v^{2} + 44 v - 30

= \frac{4 v ^{3} - 22 v ^{2} + 44 v - 30}{2 x - 3}

\frac{( s + 1 )}{( ( s ^{2} - 4 s ) ( s + 5 ) )}

\frac{10 ( 1 + 61 )}{7}

- 400 (3993 - 802)

(6 - π)^{2}

(y - \frac{3}{7}) \cdot (y + \frac{3}{7})

What is expand (2(2v^3-11v^2+22v-15))/(2x-3) ?
The solution to expand (2(2v^3-11v^2+22v-15))/(2x-3) is (4v^3-22v^2+44v-30)/(2x-3)