What is expand (a+c-cos(x)b)^2 ?

The solution to expand (a+c-cos(x)b)^2 is a^2+2ac-2abcos(x)+c^2+cos^2(x)b^2-2cbcos(x)

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expand (a+c-cos(x)b)^2

expand

(a + c - cos (x) b)^{2}

a^{2} + 2 a c - 2 ab cos (x) + c^{2} + cos^{2} (x) b^{2} - 2 c b cos (x)

Solution steps

(a + c - cos (x) b)^{2}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

(a + c - cos (x) b)^{2} = (a + c - cos (x) b) (a + c - cos (x) b)

= (a + c - cos (x) b) (a + c - cos (x) b)

Distribute parentheses

= aa + a c + a (- cos (x) b) + c a + cc + c (- cos (x) b) - cos (x) ba - cos (x) b c - cos (x) b (- cos (x) b)

Simplify

aa + a c + a (- cos (x) b) + c a + cc + c (- cos (x) b) - cos (x) ba - cos (x) b c - cos (x) b (- cos (x) b) : a^{2} + 2 a c - 2 ab cos (x) + c^{2} + cos^{2} (x) b^{2} - 2 c b cos (x)

= a^{2} + 2 a c - 2 ab cos (x) + c^{2} + cos^{2} (x) b^{2} - 2 c b cos (x)

\frac{2}{( s + 2 ) ^{2}}

5 + 1 (A cos (4 i x) + B, (4 i x))

\frac{2 x + 3}{( x - 6 ) ( x - 3 )}

(- e^{3 t} + 3 e^{t} - 2) (1.5 e^{- 3 t} - 1.5 e^{- t})

(e^{3 x}) (x + C e^{- x} + C e^{- 3 x})

What is expand (a+c-cos(x)b)^2 ?
The solution to expand (a+c-cos(x)b)^2 is a^2+2ac-2abcos(x)+c^2+cos^2(x)b^2-2cbcos(x)