What is expand (1-e^z)(z+e^z) ?

The solution to expand (1-e^z)(z+e^z) is z+e^z-e^zz-e^{2z}

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expand (1-e^z)(z+e^z)

expand

(1 - e^{z}) (z + e^{z})

z + e^{z} - e^{z} z - e^{2 z}

Solution steps

(1 - e^{z}) (z + e^{z})

Apply FOIL method:

(a + b) (c + d) = a c + a d + b c + b d

a = 1, b = - e^{z}, c = z, d = e^{z}

= 1 \cdot z + 1 \cdot e^{z} + (- e^{z}) z + (- e^{z}) e^{z}

Apply minus-plus rules

+ (- a) = - a

= 1 \cdot z + 1 \cdot e^{z} - e^{z} z - e^{z} e^{z}

Simplify

1 \cdot z + 1 \cdot e^{z} - e^{z} z - e^{z} e^{z} : z + e^{z} - e^{z} z - e^{2 z}

= z + e^{z} - e^{z} z - e^{2 z}

x d x + (y + 1) d y

(x - 10) (x - \frac{1}{2})

(cos (θ) - sin (θ)) \cdot (cos (θ))

\frac{( s + 18 )}{s ( s + 3 ) ( s + 15 ) ( s + 20 )}

\frac{( - 1 - 3 i ) ^{4}}{16}

What is expand (1-e^z)(z+e^z) ?
The solution to expand (1-e^z)(z+e^z) is z+e^z-e^zz-e^{2z}