What is expand 1/((x-a)(x-b)(x-c)) ?

The solution to expand 1/((x-a)(x-b)(x-c)) is 1/(x^3-cx^2-bx^2+bcx-ax^2+acx+abx-abc)

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expand 1/((x-a)(x-b)(x-c))

expand

\frac{1}{( x - a ) ( x - b ) ( x - c )}

\frac{1}{x ^{3} - c x ^{2} - b x ^{2} + b c x - a x ^{2} + a c x + ab x - ab c}

Solution steps

\frac{1}{( x - a ) ( x - b ) ( x - c )}

Expand

(x - a) (x - b) (x - c) : x^{3} - c x^{2} - b x^{2} + b c x - a x^{2} + a c x + ab x - ab c

= \frac{1}{x ^{3} - c x ^{2} - b x ^{2} + b c x - a x ^{2} + a c x + ab x - ab c}

4 x 3 - 7 + 10 x

(7 x - \frac{1}{2}) (7 x + \frac{1}{2})

\frac{y ^{2} ( 1 - x ^{2} )}{2}

\frac{x ( x - 1 )}{x ^{2} + 2 x + 1}

4 (3 e - 5)

What is expand 1/((x-a)(x-b)(x-c)) ?
The solution to expand 1/((x-a)(x-b)(x-c)) is 1/(x^3-cx^2-bx^2+bcx-ax^2+acx+abx-abc)