What is expand (n^2(4^n))/((n+1)(n+2)) ?

The solution to expand (n^2(4^n))/((n+1)(n+2)) is (4^nn^2)/(n^2+3n+2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (n^2(4^n))/((n+1)(n+2))

expand

\frac{n ^{2} ( 4 ^{n} )}{( n + 1 ) ( n + 2 )}

\frac{4 ^{n} n ^{2}}{n ^{2} + 3 n + 2}

Solution steps

\frac{n ^{2} ( 4 ^{n} )}{( n + 1 ) ( n + 2 )}

Remove parentheses:

(a) = a

= \frac{n ^{2} \cdot 4 ^{n}}{( n + 1 ) ( n + 2 )}

Expand

(n + 1) (n + 2) : n^{2} + 3 n + 2

= \frac{4 ^{n} n ^{2}}{n ^{2} + 3 n + 2}

- 4 (= 2 p + 10)

\frac{1}{s ^{2} ( s ^{2} - a )}

(1 - \frac{1}{( x + 28 ) ^{2}}) (1 - \frac{1}{( x + 29 ) ^{2}})

- 2 (π \cdot (x + 1)^{3}) + 37

What is expand (n^2(4^n))/((n+1)(n+2)) ?
The solution to expand (n^2(4^n))/((n+1)(n+2)) is (4^nn^2)/(n^2+3n+2)