What are the solutions to the equation 3x^2-2x-8=0 ?

The solutions to the equation 3x^2-2x-8=0 are x=2,x=-4/3

Find the zeros of 3x^2-2x-8=0

The zeros of 3x^2-2x-8=0 are x=2,x=-4/3

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3 x^{2} - 2 x - 8 = 0

x = 2, x = - \frac{4}{3}

Solution steps

3 x^{2} - 2 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 3 ( - 8 )}{2 \cdot 3}

(- 2)^{2} - 4 \cdot 3 (- 8) = 10

x_{1, 2} = \frac{- ( - 2 ) \pm 10}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 10}{2 \cdot 3}, x_{2} = \frac{- ( - 2 ) - 10}{2 \cdot 3}

x = \frac{- ( - 2 ) + 10}{2 \cdot 3} : 2

x = \frac{- ( - 2 ) - 10}{2 \cdot 3} : - \frac{4}{3}

The solutions to the quadratic equation are:

x = 2, x = - \frac{4}{3}

- 6 (n - 1) \leq 60 or 4 + n < 8

- \frac{1}{2} x^{2} + \frac{9}{4} x - 1 = 0

\frac{9 x ^{4} y ^{2}}{6 x ^{8} y}

3 x^{3} - 3 x^{2} - 18 x

2 x^{2} - 13 x - 7 = 0

What are the solutions to the equation 3x^2-2x-8=0 ?
The solutions to the equation 3x^2-2x-8=0 are x=2,x=-4/3
Find the zeros of 3x^2-2x-8=0
The zeros of 3x^2-2x-8=0 are x=2,x=-4/3