What is expand 2(x^2-4x+4-y/2 =8) ?

The solution to expand 2(x^2-4x+4-y/2 =8) is 2x^2-8x+8-y=8

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expand 2(x^2-4x+4-y/2 =8)

expand

2 (x^{2} - 4 x + 4 - \frac{y}{2} = 8)

2 x^{2} - 8 x + 8 - y = 8

Solution steps

2 (x^{2} - 4 x + 4 - \frac{y}{2} = 8)

= 2 (x^{2} - 4 x + 4 - 8 = \frac{y}{2})

Distribute parentheses

= 2 x^{2} + 2 (- 4 x) + 2 \cdot 4 + 2 (- \frac{y}{2} = 8)

Apply minus-plus rules

+ (- a) = - a

2 x^{2} - 2 \cdot 4 x + 2 \cdot 4 - 2 \cdot \frac{y}{2} = 8

Expand

2 x^{2} - 2 \cdot 4 x + 2 \cdot 4 - 2 \cdot \frac{y}{2} : 2 x^{2} - 8 x + 8 - y

2 x^{2} - 8 x + 8 - y = 8

(2 - 2)^{4}

2 (x + Δ x) (x + 5)

C (- 4, 6) P (- 2, - 3)

(3 - x) (2 + 7)

(2 - x + 8)^{2}

What is expand 2(x^2-4x+4-y/2 =8) ?
The solution to expand 2(x^2-4x+4-y/2 =8) is 2x^2-8x+8-y=8