What is expand (2s-5)/((s-3)(s-1)) ?

The solution to expand (2s-5)/((s-3)(s-1)) is (2s-5)/(s^2-4s+3)

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expand (2s-5)/((s-3)(s-1))

expand

\frac{2 s - 5}{( s - 3 ) ( s - 1 )}

\frac{2 s - 5}{s ^{2} - 4 s + 3}

Solution steps

\frac{2 s - 5}{( s - 3 ) ( s - 1 )}

Expand

(s - 3) (s - 1) : s^{2} - 4 s + 3

= \frac{2 s - 5}{s ^{2} - 4 s + 3}

(5 + 2 x) p o w e r^{3}

(- x + 6 tan (\frac{x}{6})) \cdot (6 ln (tan (\frac{x}{6}) + sec (\frac{x}{6})))

y (2 x^{2} y + y^{2} = 2 x + 13)

(a - 2)^{3}

(5 - i)^{6}

What is expand (2s-5)/((s-3)(s-1)) ?
The solution to expand (2s-5)/((s-3)(s-1)) is (2s-5)/(s^2-4s+3)